I was hoping for an elegant or effective way to multiply sequences of integers (or floats).
My first thought was to try (1, 2, 3) * (1, 2, 2) would result (1, 4, 6), the products of the individual multiplications.
Though python isn't preset to do that for sequences. Which is fine, I wouldn't really expect it to. So what's the pythonic way to multiply (or possibly other arithmetic operations as well) each item in two series with and to their respective indices?
A second example (0.6, 3.5) * (4, 4) = (2.4, 14)
解决方案
The simplest way is to use zip function, with a generator expression, like this
tuple(l * r for l, r in zip(left, right))
For example,
>>> tuple(l * r for l, r in zip((1, 2, 3), (1, 2, 3)))
(1, 4, 9)
>>> tuple(l * r for l, r in zip((0.6, 3.5), (4, 4)))
(2.4, 14.0)
In Python 2.x, zip returns a list of tuples. If you want to avoid creating the temporary list, you can use itertools.izip, like this
>>> from itertools import izip
>>> tuple(l * r for l, r in izip((1, 2, 3), (1, 2, 3)))
(1, 4, 9)
>>> tuple(l * r for l, r in izip((0.6, 3.5), (4, 4)))
(2.4, 14.0)
You can read more about the differences between zip and itertools.izip in this question.
